4. let f(x) = ⎧ ⎨ ⎩ 0 if x < 0 x if 0 ≤ x ≤ 1 2 − x if 1 < x ≤ 2 0 ifx > 2 and g(x) = ∫ x 0 f(t) dt (a) find an expression for g(x) similar to the one for f(x). (b) sketch the graphs of f and g. (c) where is f differentiable? where is g differentiable?

step-by-step :

i’m here for points.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !