find the common difference for the following sequence and fill in the missing terms. show all calculations.
-12, 10, 32, 43

Common difference = 11

Second term is -1

fourth term is 21

Step-by-step explanation:

Given:

The given sequence are.

-12, __, 10, __, 32, 43

We need to find common difference and missing terms of the given sequence.

Solution:

The difference between two consecutive number of the sequence is called common difference.

The consecutive number of the given series are 32, 43

So, the common difference is

common difference = 11

Therefore, the common difference of the given series is 11.

Now, we add first term and common difference for the first missing number of the sequence.

= -12 +11

= -1

So, the second term of the given sequence is -1.

Similarly, we add third term and common difference for the fourth missing number of the sequence.

= 10 + 11

= 21

So, the fourth term of the given sequence is 21.        

Therefore, the complete sequence is given below.

-12, -1, 10, 21, 32, 43              

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116