Afarmer grows 196kg of carrots. he sells them to a grocer who divides them into 5kg and 2kg bags. if the grocer uses the same number of 2kg and 5kg bags, how many of each does he use? explain your thinking.

28 bags of each weight

Step-by-step explanation:

Let x be the number of 2 kg bags and 5 kg bags.

Amount of carrots in x 2-kg bags = 2x kg

Amount of carrots in x 5-kg bags = 5x kg

Total amount in all bags = 2x + 5x = 7x kg

A farmer sells 196 kg of carrots, so

Divide by 7:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )