Abdul will rent a car for the weekend. he can choose one of two plans. the first plan has an initial fee of and costs an additional per mile driven. the second plan has an initial fee of and costs an additional per mile driven. how many miles would abdul need to drive for the two plans to cost the same?

The question is missing some important details required to answer the question. I found a similar question, so I will answer using this details. If there is any differences in the details, you can still use my working by changing the value given:

Abdul will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $38 and costs an idditional $0.11 per mile driven. The second plan has an initial fee of $49 and costs an additional $0.07 per mile driven.

How many miles would Abdul need to drive for the two plans to cost the same?

275 miles

Step-by-step explanation:

Let the distance travel be X

First plan:

Initial fee: 38

Per mile: 0.11

So the total cost is

C1 = 38 + 0.11X

Second plan:

Initial fee: 49

Per mile:0.07

So the total cost is

C2 = 49 + 0.07X

Since the question asked about when the total cost be the same, we can say that C1 = C2

C1 = C2

38 + 0.11X = 49 + 0.07X

0.11X - 0.07X = 49 - 38

0.04X = 11

X = 11/0.04 = 275

At 275 miles, the cost will be the same.

the nearest power is 1.651.

means 7482 to the 1.651th power is almost equal to 2489287