Han and tyler both started running toward each other from opposite ends of a 10-mile path along the river. han runs at a pace of 12 minutes per mile. tyler runs at a pace of 15 minutes per mile. how long does it take until han and tyler meet?

The time taken by both Han and Tyler to meet at point on 10 miles path is 0.37 minutes

Step-by-step explanation:

Given as :

The distance of path on which Han and Tyler run from opposite end = d = 10 miles

The speed of Han = = 12 miles per min

The speed of Tyler = = 15 miles per min

Let The time at which both meet at a points = t minutes

Let The distance cover by Han = = d miles

And The distance cover by Tyler = = (10-d) miles

Now, According to question

Time =

So, For Han

T =

i.e T =             ....1

Again For Tyler

T =

i.e T =        .....2

Now, Equating both equations

=    

cross multiplying

15 × d = 12 × (10 - d)

Or, 15 d = 120 - 12 d

Or, 15 d + 12 d = 120

or, 27 d = 120

∴ d = =

I.e d = 4.44 miles

Now, Put the value of d in eq 1

So, Time taken = T =

I.e T = 0.37 min

So, The time taken to meet at a point = T = 0.37 min

Hence, The time taken by both Han and Tyler to meet at point on 10 miles path is 0.37 minutes  . Answer

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