Asample of 106 healthy adults have a mean body temperature of 98.2, and a standard deviation of 0.62. construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. group of answer choices ( 98.04, 98.36 ) ( 97.54, 97.95 ) ( 97.84, 98.12 ) ( 97.82, 98. 15 ) ( 97.95, 98.15 )

Step-by-step explanation:

Given : Sample size of healthy adults: n= 106

Degree of freedom = df =n-1 = 105

Sample mean body temperature  :

Sample standard deviation :

Significance level ;

∵ population standard deviation is unknown , so we use t- critical value.

Confidence interval for the population mean :

Using t-distribution table , we have

Critical value for df = 105 and =

A 99% confidence interval estimate of the mean body temperature of all healthy humans will be :

Hence, a 99% confidence interval estimate of the mean body temperature of all healthy humans =

answer: -0.5 would be the most likley outcome

step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: