First three need to be checked and last one needs to be answered.

if you cant see the attachments plz wait

Step-by-step explanation:

1. Obviously, the figure is rotated CCW by 90°. If the center of rotation were the center of the figure, the image would be in the same quadrant as the pre-image. It is in the quadrant located 90° CCW from the original, so the center of rotation must not be the center of the image. That leaves one viable answer choice.

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2. The line joining a point and its reflection is always perpendicular to (and bisected by) the line of reflection.

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3. The theorem tells you a point on the perpendicular bisector is equidistant from the endpoints of the segment bisected. If the surveyor is to apply that theorem, he needs a point equidistant from the original two stakes.

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4. The square has four (4) lines of symmetry: through the parallel side midpoints, and through opposite vertices. The corresponding lines would be ...

The appropriate choice is ...

  x + y = 4

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>