Find the 30th term of the arithmetic sequence with a first term of 4 and a comman difference of 8

236

Step-by-step explanation:

The n th term of an arithmetic sequence is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 4 and d = 8, thus

= 4 + (29 × 8) = 4 + 232 = 236

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.