The golden comet is a hybrid chicken that is prized for its high egg production rate and gentle disposition. according to recent studies, the mean rate of egg production for 1-year-old golden comets is 5.0 eggs/week. sarah has 39 1-year-old hens that are fed exclusively on natural scratch feed: insects, seeds, and plants that the hens obtain as they range freely around the farm. her hens exhibit a mean egg-laying rate of 5.2 eggs/day. sarah wants to determine whether the mean laying rate μ for her hens is higher than the mean rate for all golden comets. assume the population standard deviation to be eggs/day.

i. state the appropriate null and alternate hypotheses.
ii. compute the value of the test statistic.
iii. state a conclusion. use the level of significance.

There is not enough evidence to state that mean laying rate μ for her hens is higher than the mean rate for all Golden Comets.      

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =  5.0 eggs/week

Sample mean, = 5.2 eggs/day

Sample size, n = 39

Alpha, α = 0.05

Population standard deviation, σ = 1.1 eggs/Day

a) First, we design the null and the alternate hypothesis

We use one-tailed z test to perform this hypothesis.

b) Formula:

Putting all the values, we have

c) Now,

Since,  

We fail to reject the null hypothesis and accept the null hypothesis. Thus, mean laying rate μ for Sarah's hens is same as the mean rate for all Golden Comets.  There is not enough evidence to state that mean laying rate μ for her hens is higher than the mean rate for all Golden Comets.

answear:

a

step-by-step explanation: a

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step-by-step explanation: