If 3(d+1)=4(d–2), then what is the value of 5(d–2)?

Ans => 45

Step-by-step explanation:

3(d+1) = 4(d-2)

Expanding the brackets we have:

3d + 3 = 4d - 8

our aim now is to solve for d

3d - 4d = -8 - 3

-d = -11

=> d = 11

we can now get 5(d-2)

substituting d = 11

5(11-2)

5(9)

= 45

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

linear pair postulates