If x=3 units, y=11 units, and h=7 what is the area of the trapizoid

area of trapizoid=49 unit^2

Step-by-step explanation:

area of trapizoid=0.5(x+y)h

where, x=parallel side=3units

         y=parallel side =11 units

         h=distance between two parallel sides

area of trapizoid=0.5(x+y)h..............(1)

put x=3 units,y=11 units and h=7 in equ (1)

area of trapizoid=0.5(3+11)7

area of trapizoid=

area of trapizoid=49 unit^2 answer

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)