Suppose at a large university, 60% of the students have a visa card and 40% of the students have a mastercard. also, 30% of the students neither have 1 a visa card, nor have a mastercard. randomly select a student from the university. given that this student has a visa card, what is the probability that this student also has a mastercard1. calculate the probability that this student does not have a mastercard. 2. calculate the probability that this student has either a visa card or a mastercard. 3. calculate the probability that this student has neither a visa card nor a mastercard. 4. are the events a and b disjoint? are the events a and b independent?

0.6,0.7,0.3 neither disjoint nor independent.

Step-by-step explanation:

Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.

A= visa card

B = Master card

P(A) = 0.60 and P(B) = 0.40

P(AUB)' = 0.30

i.e. P(AUB) = 0.70

Or P(A)+P(B)-P(AB) =0.70

P(AB)= 0.30

Randomly select a student from the university.

1) the probability that this student does not have a MasterCard.

2.  the probability that this student has either a Visa card or a MasterCard.

=

3. Calculate the probability that this student has neither a Visa card nor a MasterCard.

=

4. Are the events A and B disjoint? Are the events A and B independent?

A and B have common prob 0.30 hence not disjoint.

P(AB) ≠P(A)P(B)

Hence not independent

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.

c

step-by-step explanation: