Find the equation of the line specified. the slope is 7, and it passes through ( 8, 6).
a. y = 7x - 50
c. y = 7x + 6
b. y = 14x - 50
d. y = 7x + 62
determine the slope and y-intercept of the line. y = 5x + 4
a. slope = 4, y-intercept is (0, 5)
c. slope = 5, y-intercept is (0, 4)
b. slope = -5, y-intercept is (0, 4)
d. slope = 4, y-intercept is (0, -5)
find the equation of the line specified. the slope is 6, and it passes through ( -4, 4).
a. y = 6x + 4
c. y = 12x +

Part 1).

Slope of line = 7 and Passing through point = ( 8 , 6 )

We find the equation of line using point and slope form,

y - 6 = 7 ( x - 8 )

y - 6 = 7x - 56

y = 7x - 56 + 6

y = 7x - 50

Therefore, Option A is correct.

Part 2).

Given Equation of line y = 5x + 4

We have to find slope of line and y-intercept.

We compare the given equation line with slope intercept form

y = mx + c

where m = slope of line and c =  y-intercept of line.

So Slope, m = 5 and y-intercept = 4 or ( 0 , 4 )

Therefore, Option C is correct.

Part 3).

Slope of line = 6 and Passing through point = ( -4 , 4 )

We find the equation of line using point and slope form,

y - 4 = 6 ( x - (-4) )

y - 4 = 6 ( x + 4 )

y - 4 = 6x + 24

y = 6x + 24 + 4

y = 6x + 28

Therefore, Equation Of line is y = 6x + 28

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tangent

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