Every day going to school, june has to go by boat (point a) over a 217m-wide river to point b (the other bank), and then from b walk to school at point d with distance ad = 170m. in fact, due to the flowing water, the boat was pushed by the water at an angle of 50 degrees and brought her to point c (the other shore). from c, june walk to school. calculate the distance june traveled from a to d. (result rounded to the third decimal place)

Explanation:

The distance traveled by June, from A to D, is the sum of the distance from A to C plus the distance from C to D:

1) Find the distance AC

2) Find the distance DC

First, you need to calculate the side BC which is a common side of both triangles ABC and DBC.

You can use Pythagora's or a trigonometric function (tangent or sine).

Now you can use Pythagora's theorem to find the distance DC, which is the hypotenuse of the triangle DBC:

3) Find the total distance traveled from A to D

it’s supposed to be -4+45=41

step-by-step explanation: