Asoft-drink machine is regulated so that it discharges an average of 200 mililiters per cup. if the amount of drink is normally distributed with a standard deviation equal to 15 mililiters, what fraction of the cups will contain more than 224 mililiters?

0.0548

Step-by-step explanation:

Mean(μ) = 200 mm/ cup

Standard deviation (σ) = 15 mm/cup

Let X be the amount of drink distributed.

Pr(x>224) =

Since it is normally distributed

Z = (x - μ)/σ

Z = (224 - 200)/ 15

Z = 24/15

Z = 1.6

From the normal distribution table, 1.6 = 0.4452

Φ(z) = 0.4452

If Z is positive, Pr(x>a) = 0.5 - Φ(z)

Pr(x >224) = 0.5 - 0.4452

= 0.0548

answer: i believe c. is the answer sorry if i am wrong

step-by-step explanation:

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40