There is an 80% chance david will eat a healthy breakfast and a 25% chance that it will rain. if these events are independent , what is the probability that david will eat a healthy breakfast or that it will rain?

The probability that David will eat a healthy breakfast or that it will rain is 0.85 or 85%.

Step-by-step explanation:

Consider the provided information.

There is an 80% chance David will eat a healthy breakfast.

P(H) = 0.8

There is a 25% chance that it will rain.

P(R) = 0.25

The probability of David will eat a healthy breakfast and it will rain is:

P(H ∩ R)  = 0.8 × 0.25 = 0.2

P(H ∪ R) = P(H) + P(R) - P(H ∩ R)

P(H ∪ R) = 0.8 + 0.25 - 0.2

P(H ∪ R) = 0.85

Hence, the probability that David will eat a healthy breakfast or that it will rain is 0.85 or 85%.

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

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