7)
hookes law for an elastic spring states that the distance a spring stretches varies directly as the
be applied. if a force of 15 pounds stretches a certain spring 7 inches, then how much will a force
of 60 pounds stretch the spring?
d) 3 in.
a) 2 in.
c) 28 in
b) 105 in

C) 28 in.

Step-by-step explanation:

Given:

Hooke's Law for an elastic spring states that "the distance a spring stretches varies directly as the  force to be applied."

Hence we can say that;

F ∝ D

F = k . D

where,

F ⇒ Force applied

D⇒ Distance of spring

k⇒ constant

Now Given:

Force (F) = 15 pounds

Distance of Spring (D) = 7 inches

Substituting the values in above equation we get;

Now we need to find Distance of the spring stretched when Force is 60 pounds.

Substituting the values we get;

Hence the distance of spring stretched will be 28 inches when a force of 60 pounds applied to it.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632