You can work at most 11 hours next week. you need to earn at least $60 to cover your weekly expenses. your dog-walking job pays $9 per hour and your job as a car wash attendant pays $6 per hour. let d = the # of hours you walk dogs and c = the # of hours you wash cars.

write a system of linear inequalities representing the situation and identify 2 solutions to the system.

2 possible solutions are c = 7, d = 3 and c = 8, d = 2

Step-by-step explanation:

Let d be the number of hours you walk dogs and c be the number of hours you wash cars. Note that

1. You can work at most 11 hours next week, so

2. Your dog-walking job pays $9 per hour, so for d hours you will earn $9d. Your job as a car wash attendant pays $6 per hour, then for c hours you will be paid $6c. In total, you will earn $(9d+6c) that must be at least $60.

So,

3. You get following system of inequalities:

The diagram shows the solution set to the system of these inequalities.

2 possible solutions are c = 7, d = 3 and c = 8, d = 2

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240