Use the value of the first integral i to evaluate the two given integrals. i = integral^3_0 (x^3 - 4x)dx = 9/4 a. integral^3_0 (8x - 2x^3)dx b. integral^0_3 (4x - x^3)dx c. integral^3_0 (8x - 2x^3)dx =

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that . We use the properties of integrals to write the new integrals in terms of I.

A) . We have used that ∫cf dx=c∫f dx.

B) . Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

if i put something wrong your not gonna like it so rather not say nothing.