Use the matrix capabilities of a graphing utility to write the augmented matrix corresponding to the system of equations in reduced row-echelon form. then solve the system. (if there is no solution, enter no solution. if the system is dependent, express x, y, z, and w in terms of the parameter

a.) x + 2y + z + 3w = 0 x − y + w = 0 y − z + 2w = 0 (x, y, z, w) =

x =-2t , y = -t, z= t

Step-by-step explanation:

x+2y+z+3w=0

x-y+w=0

y-z+2w=0

The augmented system would be given by:

Now we can do operations in order to reduce it to the row echelon form

1) R1 *(-1) + R2

2) R2 *(-1/3)

3) R2*(-1)+R3

4) R3*(-3/4)

5) R3(-1/3) + R2; R3(-1) +R1

6) R2(-2) +R1

Let w=t a free variable then the solution is given by:

x =-2t , y = -t, z= t

40 is the final : )

only 10/60 isn't equivalent

hope this : )