The 3rd degree taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − x − π 2 + 1 6 x − π 2 3 + r3(x). using this, estimate cos(88°) correct to five decimal places.

0.034899

Step-by-step explanation:

There are quite a few mistakes in writing the the question, but i corrected them below. firstly the value of a that you stated seems incorrect and based on the last part of the question asking for cos(88°) i figured that what you were trying to write down was a=π/2 , since 88° is in the vicinity of a=π/2 or 90° and thats what the taylor series expansions are all about, that is estimating the values of functions about a given point. The second problem was in writing down the taylor series itself. So i used the formula for the taylor series expansion and obtained the correct version about the point a=π/2 that is,

In the last step we converted degrees into radians and then plugged it in.

If you use the calculator to evaluate cos(88°) you would get the same result to 5 decimal places.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

the answer is c.

step-by-step explanation: