Atriangle has sides qp and rq of triangle pqr are produced to points s and t respectively if< spr=135° and < pqt=110°, find < prq

∠ PRQ = 65°

Step-by-step explanation:

See the diagram attached.

The ∠ PQR and ∠ PQT are supplementary.

So, ∠ PQR = 180° - 110° = 70° {Since given that ∠ PQT = 110°}

Again, ∠ SPR and ∠ RPQ are supplementary.

So, ∠ RPQ = 180° - 135° = 45° {Since, given that ∠ SPR = 135°}

Now, from Δ PQR, ∠ PQR + ∠ RPQ + ∠ PRQ = 180°

⇒ 70° + 45° + ∠ PRQ = 180°

⇒ ∠ PRQ = 180° - 70° - 45° = 65° (Answer)

answer: i cant see the picture

step-by-step explanation:

can u take a better picture

a. 74 degrees

step-by-step explanation:

because the lines through the side and the box in the corners shows that these are congruent triangles and since they are mirrored the 37 degrees is also mirrored so the answer is 37 * 2 which is 74.