The escalator rises 25° from the ground and a vertical distance of 42 feet. how much horizontal distance does the escalator cover? round to the nearest tenth.

90.1 feet.

Step-by-step explanation:

Please find the attachment.

Let x represent horizontal distance.

We have been given that an escalator rises 25° from the ground and a vertical distance of 42 feet. We are asked to find horizontal distance covered by escalator.

We can see from our attachment that vertical distance is opposite side of 25 degree angle and horizontal distance is adjacent side.

We know that tangent relates opposite side of right triangle with adjacent.

Upon substituting our given values, we will get:

Therefore, the escalator covered a horizontal distance of 90.1 feet.

i can't read the graph

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°