Amarine biologist is setting up a net 6 feet below the surface of the water. each foot of the water screens out 40% of the light coming from the surface. which of the following is the approximate percentage of light remaining after passing through 6 feet of water, to the nearest tenth of a percent?

The correct answer is C. 4.7%

Correct statement and question:

A marine biologist is setting up a net 6 feet below the surface of the water. Each foot of the water screens out 40% of the light coming from the surface. Which of the following is the approximate percentage of light remaining after passing through 6 feet of water, to the nearest tenth of a percent?

0.4%

1.0%

4.7%

7.8%

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Step-by-step explanation:

1. Let's review all the information given to us to answer the question correctly:

Depth of the net = 6 feet below the surface of the water

Each foot of the water screens out 40% of the light coming from the surface.

2. Which is the approximate percentage of light remaining after passing through 6 feet of water, to the nearest tenth of a percent?

After one feet: 100 - 40 = 60%

After two feet = 60 - 0.4 * 60 = 60 - 24 = 36

After three feet = 36 - 0.4 * 36 = 36 - 14.4 = 21.6

After four feet = 21.6 - 0.4 * 21.6 = 21.6 - 8.64 = 12.96

After five feet = 12.96 - 0.4 * 12.96 = 12.96 - 5.18 = 7.78

After six feet = 7.78 - 0.4 * 7.78 = 7.78 - 3.11 = 4.67 = 4.7 (Rounding to the nearest tenth)

The correct answer is C. 4.7%

its d. the first coordintaes are 10,32

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.