According to the national telecommunication and information administration, 56.5% of u. s. households owned a computer in 2001. what is the probability that of three randomly selected u. s. households at least one owned a computer in 2001?

Step-by-step explanation:

Assuming a binomial distribution for the number of U.S. households that owned a computer in 2001. The formula for binomial distribution is expressed as

P(X = r) = nCr × q^(n - r) × p^r

Where

p = probability of success

q = probability of failure

n = number of sample

From the information given,

p = 56.5% = 56.5/190 = 0.565

q = 1 - p = 1 - 0.565 = 0.435

n = 3

We want to determine P(x greater than or equal to 1). This is also expressed as

1 - P(x lesser than or equal to 1)

P(x lesser than or equal to 1) = P(x = 0) + P(x =1)

P(x = 0) = 3C0 × 0.435^(3 - 0) × 0.565^0 = 0.082

P(x = 1) = 3C1 × 0.435^(3 - 1) × 0.565^1 = 0.32

P(x greater than or equal to 1) = 0.082 + 0.32 = 0.402

c

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺