Afamily has three children. using b to stand for a boy and g for girl give the following.(to indicate that the first child is a boy, the second child is a boy, and the third child is a girl enter bbg. enter your answers as a comma-separated let the event e that the family has exactly two boys.

a) find the probability p(e)
b) find the odd o(e) part a): [select ] part b): iselect ) ?

3/8 and 3/5

Step-by-step explanation:

Given that a family has three children. Using b to stand for a boy and g for girl give the following we can write sample space for a family having three children as

(bbb, bbg, bgg, bgb, gbb, gbg, ggb, ggg)

E - exactly two boys

Sample space count = 8

Exactly two boys count = 3

a) p(E) =

b) odds for E is probability/1-probability

=

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: