Asolve any one of the following subquestions :
6) construct a word problem on simultaneous linear equations in two variables
(on age, rupees, metres, speed, so that the value of one variable will be 18.

Step-by-step explanation

Lisa and Tom are going door to door selling raffle tickets. Lisa has already collected more money then Tom. In fact, she has collected $ 14 more dollars then Tom. Together, they have collected $ 22. How much money did each one collect ?

x = amount of money Lisa collected

y = amount of money Tom collected

x = 14 + y

x + y = 22

solve :

sub in 14 + y for x back into the second equation

x + y = 22

14 + y + y = 22

14 + 2y = 22

2y = 22 - 14

2y = 8

y = 8/2

y = 4Tom has collected $ 4

now sub 4 in for y back into either of the original equations

x + y = 22

x + 4 = 22

x = 22 - 4

x = 18 Lisa has collected $ 18

answer is:

1.75 pounds

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2