Ill give brainiest.
main show tank calculation:

the main show tank has a radius of 70 feet and forms a quarter sphere where the bottom of the pool is spherical and the top of the pool is flat. (imagine cutting a sphere in half vertically and then cutting it in half horizontally.) what is the volume of the quarter-sphere shaped tank? round your answer to the nearest whole number. you must explain your answer using words, and you must show all work and calculations to receive credit.
holding tank calculations:

the holding tanks are congruent. each is in the shape of a cylinder that has been cut in half vertically. the bottom of each tank is a curved surface and the top of the pool is a flat surface. what is the volume of both tanks if the radius of tank #1 is 35 feet and the height of tank #2 is 120 feet? you must explain your answer using words, and you must show all work and calculations to receive credit.

21,984.44581% of change

Step-by-step explanation:

First you want to use the formula for cylinders which is V = pi r^2 h

V = 3.14 (15)^2 (120)

V = 3.14 (225) (120)

V = (706.5) (120)

V = 84,780 ft.

This volume (84,780) would be the volume of a whole tank, but since both the tanks are only half a cylinder, the volume of each holding tank would be half this number. Therefore, 84,780/2= 42390 ft which is the volume of each individual holding tank, but since we have 2 holding tanks we would multiply 42390 by 2 which is 84,780 ft (the volume of both the holding tanks together).

The volume of the mock-up is 1/216 times smaller making it be

3 times smaller.

If all linear dimensions are 6 times smaller then that means we take 6 to the third power which is 216.

The mock up would be 3 times smaller.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.