Amajor-league baseball team plays 162 games each season. so far this season, rosanne’s favorite team has won 17 games and lost 10 games. if the team continues to win at the same rate, how
many games will rosanne’s favorite team win?

Explanation:

Let's say that the team plays 27 games in the first month of the season. Of those 27 total games, they win 17 and lose 10

A = number of wins = 17

B = total number of games played in first month = 27

Now let's extend it out to a whole season

C = number of wins in the season = unknown

D = total number of games played in a season = 162

If the winning rate stays the same as it did in the first month, then we can set up the proportion below

A/B = C/D

from here plug in the given values and solve for C

A/B = C/D

17/27 = C/162

17*162 = 27*C ... cross multiply

2754 = 27*C

27C = 2754

27C/27 = 2754/27 ... divide both sides by 27

C = 102

The team will win 102 games total throughout the season assuming the team wins at the same rate as the first month.

Note how

A/B = 17/27 = 0.62962962962962

C/D = 102/162 = 0.62962962962962

both fractions produce the same decimal number, so the two fractions are equal to one another. The winning rate is roughly 62.96%

a is the correct

r = 78539458390583095803458309458039485093485 or just 3

step-by-step explanation: