What is the length of a rectangle with width of 10 in and area of 62 in?

answer:

step-by-step explanation:

area of rectangle = 62 sq.in

length   * width = 62

length * 10 = 62

length = 62/10 =6.2

length = 6.2 inches

answer:

l = 6.2 in

step-by-step explanation:

you find a rectangle area using the formula:

a = l . w , where l is the length and w is width.

with you're trying to find the lenght and you have these informations:

a = 62in² and w = 10in,

let's apply in the formula

62 = l . 10

solving this equation, you'll find l = 6.2 in

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

.25

step-by-step explanation: