At 5: 00 p. m., the outside temperature was –9.2°c. by 10: 00 p. m., the outside temperature had dropped 4.5°c.

what was the outside temperature at 10: 00 p. m.?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

21.4 i did it already for s1

step-by-step explanation: