Find the 70th term of the arithmetic sequence 29, 17, 5,

 - 799

Step-by-step explanation:

The term of a sequence

Tn = a + ( n - 1 )d where a = first term , n = the number of terms and d = the common difference.

From the Arithmetic Sequence, a = 29, n = 70 while d = 17 - 29 = -12

To calculate d, always deduct the first term from the second term and so on.

Now substitute for the values in the formula to find the 70th term

T(70) = 29 + ( 70 - 1 ) x -12

        = 29 + 69 x -12

        =   29 - 828

       =  -799.

Therefore the 70th term of the sequence

    = -799

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9