Ann's watch runs 2 minutes per hour too slow. beth's watch runs 1 minute per hour too fast. for example, if both watches were correct at 12p. m on a given day, then at 1: 00pm, ann's watch would read 12: 58pm and beth's would read 1: 01 pm. ann and beth set their watches to the correct time at noon on sunday. the next time they met, one of the watches was one hour ahead of the other. what was the earliest time this could have been?

8 am Monday

Step-by-step explanation:

The difference between the two watches is  2+1= 3 minutes.

It would take 60/3 = 20 hours to have a difference of 60 minutes.

From noon Sunday it would be more 20 hours the earliest time there would be a difference of one hour between the two watches' time.

12 noon + 20 hours=  8 am Monday

the answer

b. they are parallel and will never intersect.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15