Solve for y, z, x or t:

y+y/a=b if a≠-1 , find y.

z−a=z/b if b≠1 , find z.

: ( i keep asking and no one answers. if you could at least answer one of them then that would be marking brainliest. must have explanation.

Problem 1

y + (y/a) = b

a*( y + (y/a) ) = a*b ... multiply both sides by 'a'

ay + a(y/a) = ab ... distribute

ay + y = ab

(a+1)y = ab factor

y(a+1) = ab

y = ab/(a+1) ... divide both sides by (a+1)

Problem 2

z - a = z/b

b(z - a) = b(z/b) multiply both sides by b

b(z - a) = z

bz - ab = z ... distribute

bz - ab+ab = z+ab ... add ab to both sides

bz = z+ab

bz-z = z+ab-z ... subtract z from both sides

bz-z = ab

z(b-1) = ab factor

z = ab/(b-1) divide both sides by (b-1)

Notes:

To clear out the fractions, I multiplied both sides by the denominator value.

The restriction that 'a' cannot equal -1, back in problem 1, is to avoid having the denominator (a+1) be equal to zero. We cannot divide by zero. A similar situation happens with problem 2 as well.

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point