The graph of which function passes through (0,3) and has an amplitude of 3? f (x) = sine (x) + 3 f (x) = cosine (x) + 3 f (x) = 3 sine (x) f (x) = 3 cosine (x)

Step-by-step explanation:

We are looking for a trigonometric function which contains the point (0, 3), and has an amplitude of 3.

We know that for a sine function , ; therefore the function we a looking for cannot be a sine function because it is zero at .

However, the cosine function gives non-zero value at

therefore, a cosine function can be our function.

Now, cosine function with amplitude has the form

this is because the cosine function is maximum at and therefore, has the property that

in other words it contains the point .

The function we are looking for contains the point ; therefore, its amplitude must be 3, or

we see that this function satisfies our conditions: has amplitude of 3, and it passes through the point (0, 3) because

00

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3