Seattle star blends whole bean coffee worth $3.00 per pound to get 25 pounds of a coffee blend worth $3.50 per pound. how many pounds of both blends does she use?

Blend of Whole bean coffee used = 22.5 Ib

Blend of Half bean Coffee used = 2.5 lb

Correction in statement:

The problem statement is missing information. The proper statement is as follows:

Seattle Star blends whole bean coffee worth $3 per pound with half bean coffee worth $3.5 per pound to get 25 pounds of a coffee blend worth $3.05 per pound. How many pounds of each type of coffee does she use?

Step-by-step explanation:

Whole Bean Coffee = $3

Half Bean Coffee = $ 3.5

Amount of whole bean coffee in Pounds (lbs) = Y

Mixture amount of whole bean and half bean blend = 25 lbs

Amount of half bean coffee = 25-Y (lbs)

Total blended mixture = $3.05

Cost of mixture = Cost of whole bean coffee used + Cost of half bean coffee used

3.05 (25) = 3Y + 3.5 (25-Y)

76.25 = 3Y + 87.5 - 3.5 Y

76.25 - 87.5 = 3Y - 3.5Y

- 11.25 = - 0.5 Y

or

0.5 Y = 11.25

Y=

Y= 22.5 lb

Which is the amount of whole bean coffee.

Amount of half bean coffee = 25-Y = 25- 22.5 = 2.5 lb

So,

Blend of Whole bean coffee used = 22.5 lb

Blend of Half bean Coffee used = 2.5 lb

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: