Specify when the magnitude of the acceleration of the block reaches its maximum value. consider the following options: only once during one period of motion, when the block's speed is zero, when the block is in the equilibrium position, when the block's displacement equals either a or −a, when the block's speed is at a maximum.

When the Block's speed is at maximum

Step-by-step explanation:

From the formula of find acceleration

acceleration = speed/time

So we can tell that acceleration is directly proportional to speed

So when the speed reaches its maximum, acceleration is also maximum, when the speed starts reducing, acceleration also reduced,

Note: talking to account initial and final speed, if these are both the same, for a specific time, acceleration will become zero, because the change in velocity within that specific time is also zero

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%