It is given that and are right angles, and . since they contain right angles, δabr and δacr are right triangles. the right triangles share hypotenuse , and reflexive property justifies that . since and , the transitive property justifies . now, the hypotenuse and leg of right δabr is congruent to the hypotenuse and the leg of right δacr, so by the hl congruence postulate. therefore, by cpctc, and bisects by the definition of bisector.

8 2/3 is the answer

step-by-step explanation: just use a calculator

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

i dont get the question

step-by-step explanation: