The end points of a diameter of a circle are (6,2) and (-4,7).
what is the standard form of the equation
enter any fraction is simplified form

Step-by-step explanation:

The standard form equation of a circle with radius r is expressed as

( x − h )^2 + ( y − k )^2 =r ^2 ,

where r represents the radius

h and k are the coordinates of the center of the circle C( h , k )

To determine the coordinates at the center of the circle, the midpoint formula would be used. It is expressed as

[(x1 + x2)/2 , (y1 + y2)/2]

Midpoint of the circle =

(6 - 4)/2 , (2 + 7)/2 = (1, 4.5)

h coordinate of the center = 1

k coordinate of the center = 4.5

r^2 = (x - h)^2 + (2 - k)^2

r^2 = (6 - 1)^2 + (2 - 4.5)^2

r^2 = 5^2 + (- 2.5)^2 = 25 + 6.25

r^2 = 31.25

Substituting r^2 = 31.25, h = 1 and k = 4.5 into (x − h )^2 + ( y − k )^2 = r^2, the standard equation of the circle becomes

(x − 1 )^2 + ( y − 4.5 )^2 = 31.25

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

correct answer:

a + bi