How should this relationship be classified?

Domain = -2, range = -5

Domain =>0, range = 0

domain = 2, range = 5

let y =>f(x)

It can be seen that Function can be linear having common difference 2

F(x) = 2x + 1 for x>0

is satisfied for above values

let's check

F(2) = 2(2)+1 = 4+1 = 5 As given

For x<0 , F(x) = 2x -1

f(-2)= 2(-2) -1= -4-1= -5 As given

For X= 0, F(x)= 2x

So , F(0) = 0 As given

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%