The value of y varies inversely as the square of x, and y=4, when x=3.

find the value of x when y=9

The value of x when y = 9 is x = 2 or x = -2

Solution:

Given that value of y varies inversely as the square of x, and y=4, when x=3.

Therefore the initial statement is:

To convert to an equation, multiply by k, the constant  of variation

 --- eqn 1

Given that,

y = 4 when x = 3

Now find value of k

Find the value of x when y = 9

x = ?

y = 9

From eqn 1,

Thus value of x is found

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

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