For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). if t is the sum of the first 10 terms in the sequence, then t isa. greater than 2b. between 1 and 2c. between 1/2 and 1d. between 1/4 and 1/2e. less than 1/4

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as .

where k is from 1 to 10.

By the given expression sequence will be

In this sequence first term "a" =

and common ratio in each successive term to the previous term is 'r' =

r =

Since the sequence is infinite and the formula to calculate the sum is represented by

[Here r is less than 1]

S =

Now we are sure that the sum of infinite terms is .

Therefore, sum of 10 terms will not exceed

Now sum of first two terms =

Now we are sure that sum of first 10 terms lie between and

Since

Therefore, Sum of first 10 terms will lie between and .

Option D will be the answer.

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400