Arectangular area is to be enclosed by a wall on one side and fencing on the other three sides. if 18 meters of fencing is are used, what is the maximum area that can be enclosed?
a: 9/2 m^2

b: 81/4 m^2

c: 27 m^2

d: 40 m ^2

e: 81/2 m^2

Explanation:

Let L be the length and W be the width.

We have only 2 sides are fenced

         Fencing = 2L + W

Fencing = 18 m

          2L + W = 18

           W = 18 - 2L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (18-2L) = 18 L - 2L²

For maximum area differential is zero

So we have

      dA = 0

      18 - 4 L = 0

        L = 4.5 m

      W = 18 - 2 x 4.5 = 9 m

Area = 9 x 4.5 = 40.5 m² = 81/2 m²

Option E is the correct answer.

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.