Assume the random variable x is normally distributed, with mean u=50 and standard deviation sd=6. find the 15 th percentile.

44.85.

Step-by-step explanation:

We have been given that the random variable X is normally distributed, with mean u=50 and standard deviation SD=6. We are asked to find the 15th percentile.

We will use normal distribution table to find the z-score corresponding to 15th percentile or 0.15.

Using normal distribution table, we will get z-score of .

Now, we will use z-score formula to find corresponding x-value to z-score of .

, where,

z = Z-score,

x = Sample score,

= Mean,

= Standard deviation.

Upon substituting our given values, we will get:

Therefore, the 15th percentile is 44.85.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier