Apath of a toy rocket thrown upward from the ground at a rate of 208 ft/sec is modeled by the quadratic function h(t) = -16t +208t. when will the rocket reach its maximum height? what will be the maximum height?

The time = 6.5 seconds and the maximum height reached by the rocket = 676 feet

Step-by-step explanation:

A path of a toy rocket thrown upward from the ground at a rate of 208 ft/sec is modeled by the quadratic function h(t) = -16 +208t.

We have to find when the rocket will reach its maximum height.

When the rocket reaches its maximum height, = 0.

h(t) = -16 +208t

= - 32t + 208 = 0

t = 6.5 seconds

At t = 6.5 seconds it is at maximum height.

Maximum height = - 16

                            = 676 feet

Time taken = 6.5s . Maximum height = 676 feet.

Step-by-step explanation:

To find the maxima of height function use differentiation ie, h(t) will be maximum when .

⇒ -32t +208 = 0

32t = 208

For maximum height put t = 6.5  in h(t),

Maximum height = -16×6.5×6.5  + 208×6.5

=676 feet.

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27 +27 or 27times 2=54

the diffrence is 0