Arectangular room is 12 feet wider than its a long how many 1 ft.² tiles does it take to tile along the inside of the room let x represent the length of the room

Number of of tiles will be  .

Step-by-step explanation:

Given:

let 'x' represent the length of the room.

Width is 12 feet wider than its length.

Width =

Area of tiles =

We need to find number of tile along the inside of the room.

First we will find Area of room.

Area of room will be equal to length times width.

framing in equation form we get;

Area of room = sq. ft.

Now Number of Tiles will be equal to Area of room divided by Area of tile.

framing in equation form we get;

Number of Tiles =

Hence Number of of tiles will be  .

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!