Introduction to the triangle midsegment theorem‼️ can someone me find bc, de, and ce ❓

Part 1)

Part 2)

Part 3)

Step-by-step explanation:

we know that

The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

so

Part 1) Find the length of  BC

Applying the Midpoint Theorem

we have

substitute the given value

solve for BC

Part 2) Find the length of  DE

Applying the Midpoint Theorem

we have

substitute the given value

Part 3) Find the length of  CE

we know that

----> by addition segment postulate

The point E is the midpoint segment BC

That means

so

we have

substitute

solve for CE

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9