Aroom has dimensions 6.8m x 9.2m. steven wants to paint the walls of the room. a large tin of paint covers 20m^2 and cost £11.75. ignoring windows and doors, and allowing for 2 coats of paint, how much will it cost steven to paint the room.

Total cost to paint the room = £73.51

Step-by-step explanation:

Given:

Dimensions of the room = 6.8 m 9.2 m

Cost of tin of paint = £11.75

A tin of paint covers an area = 20

To find the cost of painting the room with two coats of paint.

Solution:

Area of the room =

We will use unitary method to find the amount of paint required for the room.

If of area is covered by 1 tin of paint.

For of area, amount of paint required = of a tin

Then, for amount of paint required = tins of paint.

For double coats twice paint must be required.

So, total amount of paint required for painting the room with two coats of paint = tins of paints.

Using unitary method to find total cost.

If 1 tin of paint costs = £11.75

6.256 tins of paint will cost =

Total cost to paint the room = £73.51

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a

a) 40 more; b) old factory:   10%, new factory:   16%; c) week 4

explanation:

a) at week 0, we see in the graph that the new factory produces 190 specialty items.  

using the function, substituting 0 in for w,

this is a difference of 230-190 = 40.

b) the function for the old factory is written in the form f(x) = a(1+r)ˣ, where a is the original amount, x is the amount of time and r is the growth rate.   the equation for the old factory is ; 230 is in place of a and is the original amount; w is the amount of time; which means 1+r = 1.1.   this means that r must be 0.1 or 10%.

for the new factory, we find the percent of increase to find the growth rate; the formula for this is

between the first two points, the amount of change is 220-190 = 30; this gives us

30/190 = 0.158 ≈ 0.16 = 16%

c) at week 0, the old factory has 230 while the new factory has 190.

at week 1, the old factory has 230(1.1) = 253 while the new factory has 220.

at week 2, the old factory has 230(1.1²) = 278.3 while the new factory has 252.

at week 3, the old factory has 230(1.1³) = 306.13 while the new factory has 290.

at week 4, the old factory has 230(1.1⁴) = 336.743 while the new factory has 337.   this is the first week that the new factory surpasses the old.