What isthe turning point of the parabola equation isy=(x+2)(x-8)

(3, - 25 )

Step-by-step explanation:

Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0

The the x- coordinate of the turning point is

x = -

Given

y = (x + 2)(x - 8) ← expand factors using FOIL

  = x² - 6x - 16 ← in standard form

with a = 1 and b = - 6, thus

x = - = 3

Substitute x = 3 into the equation for corresponding value of y

y = (3 + 2)(3 - 8) = 5(- 5) = - 25

turning point at (3, - 25 )

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