The tens digit of a two-digit number is 3 less than the units digit. find the original number, if the sum of that number and the number reversed is 143.

The two digit number needed is valued 58.

Given that:

The tens of a two digit number  =  unit's digit - 3

Number reversed  + The number itself = 143

Let the ones digit of that two digit number be x and the tens digit be y. Then by place value concept, we have:

Since the tens digit = unit digit - 3

Thus we have:

or the number is :

Now sum of the number and the number reversed is 143, which means:

Thus, the number is  

Thus, the two digit number needed is valued 58.

Learn more about the sum of digits of a number:

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Let...

x=ones digit

x-3=tens digit

The number in terms of x would be...

10(x-3)+x = 11x-30

The number with its digits reversed would be...

10(x)+x-3 = 11x-3

And...

11x-30+11x-3=143     We can solve for x!

22x=176

x=8

The number would be 58.

58

a

step-by-step explanation: